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20x+40-x^2-2x=121
We move all terms to the left:
20x+40-x^2-2x-(121)=0
We add all the numbers together, and all the variables
-1x^2+18x-81=0
a = -1; b = 18; c = -81;
Δ = b2-4ac
Δ = 182-4·(-1)·(-81)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-18}{-2}=+9$
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